# Solving equations with variables on both sides

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• 2(m+10) = 4(m-15)
• The problem is 2(m+10) = 4(m-15). You have to first use the distribution process. ﻿
• 2m+20 = 4m-60
• It will then be 2m+20﻿ = 4m-60. You then need to find the smallest variable and subtract it from both sides.
• 20 = 2m-60
• That will make it be 20 = 2m-60. The next step is that you have to subtract 60 from both sides.﻿
• 80 = 2m
• That will make it 80 = 2m. You then need to divide 80 by 2.
• m = 40
• ﻿Making the answer m = 40.
• ﻿
• ﻿Write this down in your notebooks.
• 2(m+10) = 4(m-15) 2m=20 = 4m-60     -2            -2        20 = 2m-60 +60         +60  80 = 2m        /2 m = 40
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