By tseth, Updated
Project for Mr.Neild
The Bathtub Problem
Ella! Can you help me?
For example, if there is 7 gallons in the tub you would put that 7 in where the y goes. 7=-3/20x+19 Then solve the equation. Another example is if it has been 20 seconds and you need to figure out how many gallons is in the tub. You would put the 20 where the x goes. Y=-3/20(20)+19 Then solve the equation.
I always wondered how long it took for the water to drain but its taking to long. Its been 40 seconds and there is 13 gallons in there.
Well now its been a minute and there is 10 gallons left. You have to figure out the m and b in y=mx+b
M=-3/20 and b=19. X is the amount of time and y is amount of gallons. For the equation y=mx+b you plug in the m and b and substitute y and x with a amount of time and the y with a amount of gallons.
So the equation could be 13=-3/20(40)+19?
Exactly! If you wanted to know how many gallons is in the tub at a certain time or if you want to find out the amount of seconds if you know the amount of gallons you could just plug it into the equation.
Thank you so much! Now I don't have to wait anymore! I can just do the math.
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