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Here's an example, Let us determine the area of a sector and the segment. Note that the central angle measures 60
Let's find the area of a sector and the area of a segment if the radius of the circle is 12 cm and the central angle is 60 °. °. Solution: Area of a sector = n360 x πr2 = n360 x 𝜋r2 = 60360 x π122=24π = 60360 x 𝜋122=24𝜋 or Approximately 75.398 Area of ΔAOC ∆AOC = 12 x (12)(63–√)=363–√ = 12 x 1263=363 or approximately 62.354 Note: Area of a segment = area of a sector – area of a triangle =24π−363–√ =24𝜋−363 =75.398−62.354 =75.398−62.354 =13.044 =13.044 or 13.0 13.0 ANSWER Area of a sector =75.4 cm2 =75.4 cm2 Area of triangle =62.4 cm2 =62.4 cm2 Area of segment =13.0 cm2 =13.0 cm2 We can also use the formula A= 12acsinB A= 12acsin⁡B to get the area of the triangle. Using the radius 12 cm and the included 60-degree angle, the area of a triangle is: A= 12 (12)(12)(sin60°) A= 12 1212sin⁡60° = 12(12)(12)3–√2 = 12121232 =363–√ cm2 =363 cm2
No problem Ellie, anytime!!
Wow! I learned a lot from you today Yesha. I know know know the basics about Sectors. Thanks for today!

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