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Good morning dear student .Today we will teach about solving Quadratic Equation .Using Quadratic Formula.
Just wait until discussion end. I'm sure you will
I think I Can't do it
x2−6x+5=0 ax2+bx+c=0 c=5,b=−6, c=5 x = −b ± √(b2− 4ac 2a x = −(-6)± √((-6)2− 4(1)(5) 2(1) x = 6± √36- 20 2 x = 6± √16 2 x = 6± 4 2 x = 6± 4 2
Class some Quadratic Equation Can be Solve easily using Quadratic Formula.To use the Quadratic Formula , We substitute the values of a,b and c from the standard form into the expression on the right side of the formula. Then we simplify the expression.
Bia kindly answer this equation5x2 + 6x + 1 = 0And this is for you Ian5x2 + 2x + 1 = 0
After 5 minutes
SolveSolve 5x2 + 6x + 1 = 0 Coefficients are: a = 5, b = 6, c = 1Quadratic Formula: x = −b ± √(b2− 4ac) 2a Put in a, b and c: x = −6 ± √(62 − 4×5×1) 2×5 Solve: x = −6 ± √(36− 20) 10 x = −6 ± √(16) 10 x = −6 ± 4 10x=-0.2 or -1answer:x=-0.2 or =-1
Solve 5x2 + 2x + 1 = 0Coefficients are: a=5, b=2, c=1Note that the Discriminant is negative: b2 − 4ac = 22 − 4×5×1 = −16 Use the Quadratic Formula: x = −2 ± √(−16) 10 √(−16) = 4i (where i is the imaginary number √−1) So: x = −2 ± 4i 10 Answer: x = −0.2 ± 0.4i
okay class, that's all for today, and please answer your assignment on page 32.good bye class.
good bye ma'am.
thank you for this morning ma'am.

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