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  • Hey, Aia. Do you mind if I ask you to help me with our projectile motion problem-solving assignment? I was having trouble answering it since I was absent from the discussion yesterday due to my illness.
  • Sure, Alan. Show me the problem, and I'll try my best to clearly explain how to solve it.
  • Explains the problem....
  • A skater starts to move with constant acceleration. After 15 seconds, the velocity is now 25m/s. Solve for its acceleration.
  • Oh! This is actually the most basic of all. When it comes to solving problems, I always use the GFSA format to make everything easier and clearer for myself.
  • G-GFSA format? What is it??
  • It stands for given, find, solution, and answer. However, before we get any farther, you must first visualize what’s stated in the problem in order to completely analyze it and determine what should be included in the GFSA.
  • Okay. U-uh I think the problem is about a skater who begins moving horizontally with no initial velocity because it is not stated in the problem. After 15 seconds, it already has a final velocity of 25 m/s, and the problem is looking for acceleration. This is soo hard! Am I correct?
  • That isn’t hard because you understand what the problem is trying to convey! Now that you’ve already visualize the problem, let’s move on to it’s GFSA to make it easier for us to find the answer. According to the problem and what you have stated upon analyzing it, 15 seconds (time) and 25m/s (velocity) are the given.
  • And the goal of the problem is to find acceleration, which I have no idea how to get because anything linked to math is beyond my comprehension!
  • You just need to concentrate. Since we already know what to look for, we can easily determine the formula to use. Based on our previous discussion in Science, the formula to use when looking for acceleration is A= Vx-Vix/T.
  • huh? how come?
  • When looking for acceleration, this formula works well. It derives from Vx=Vix+At, in which I move Vix to the right side, divide both sides by time, and transfer A to the front right, resulting in A= Vx- Vix/T.
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