Today I'm going to be teaching a few different things but they all connect in a certain way
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In order to find a missing side it depends on what side youre looking for. If youre looking for the hypotenuse in this example it would be 6^2+4^2=c^2 or 36+16=c^2. 52=c^2 so, we would use the square root to find c. c=7.2. The hypotenuse can be a decimal if a and b are not perfect squares. To find the leg in the second triangle, it would be 100+b^2=169. b^2=69. If you take the square root of 69 you get b=8.3
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The first thing is pythagorean thereom. The equation for pythagorean thereom is a^2+b^2=c^2. How would you find a missing side?
The Hypotenuse is x meaning the opposite side would be 19. You would use sin for this. Since the angle is 69 your equation would be "Sin69=19/x". That would turn into X times sin69=19. Divide the sin69 from both sides and you get x-19 divided by sin69. type that into a calculator and you get x=20.35
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The next part of this is Solving for a side of a triangle using trigonometry. Remember SOHCAHTOA!! S=sin, C= cos, T=tan, O=opposite, A=adjacent, H=hypotenuse
For this you would use cos. Usually for x we would use something called theta(θ). So for this problem it would be Cosθ=13/31. Since we're finding an angle we have to use inverse cos. θ=cos^-1(13/31). Put the second equation into a calculator and you'll get 65.2 degrees for your missing angle.
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The next part of this is Solving for an angle of a triangle using trigonometry. For this, when you use trig., you use the inverse of sin, cos, and tan.
Since this is a 45-45-90 special right triangle, the other angle is 45. Your equation set up would be45-45-90/L-H 9 times √2so x=9 times √2.
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The final part is Special Right Triangles. The type of special right triangle in this problem is 45-45-90. Meaning both legs are congruent and the length of the hypotenuse is √2 tmes the length of a leg.
THE END
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