Jamie and Jill's Prank War Pt2

Šmykľavka: 1
The next day, Jamie decided he was going to get even with his sister. Jamie set up a bucket on top of the door frame and plans to wait for his sister to come home and get her back. To start, the distance from the string to the bucket is 10 ft. The door frame is 6 ft. How far apart would Jamie and Jill be?
To figure it out, I need to use Pythagorean theorem!
10ft
6ft
X
Instead of using Trig, Jamie decides to use Pythagorean theorom. Jamie remember the string's distance to the bucket, and the door's height, so he decided to square root 10^2, and subtract it to 6^2, getting the answer of 8 feet
Šmykľavka: 2
Jamie! Where are You?
Down Here!
X
For Jamie's Final Prank,He's going to try and lure his sister down stairs and splash her with a water gun. He wants to get the perfect angle to get his sister. If the stairs are 8 feet wide, and the hypotenuse is 20, what angle would he need?
20ft
8ft
To start off, we should know that it is Cos, as 8 and 20 are on the hypotenuse and opposite side. Instead of using Cos, we instead replace it with Cos-1. Then, The equation turns into Cos-1 (8/20), coming out to be 66.4 or 66 degrees
Šmykľavka: 3
THE END
Uh Oh! Instead of his sister, Jill, it was his mother who came down. He immediately dropped the water gun and fell to his knees to plead with his mother, telling her that he thought someone else was coming.

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