# Math comic project #2 More Options: Make a Folding Card

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• Systems of linear equations
• Systems of linear equations
• 2j + 3k = 11 2j - 5k = 3
• For the elimination method, we are trying to figure out the value of each variable. So in order to do that, we have to separate any of the variables that can be either subtracted, added, or multiplied.
• Systems of linear equations
• Systems of linear equations
• So which variable can be either subtracted, added, or multiplied to "eliminate" it.
• The different types are: Elimination method Substitution method One solution problems No solution problems and Infinite solution problems
• Subtract 2j?
• Systems of linear equations
• Systems of linear equations
• Yes! Excellent! You would subtract and cancel out 2j while adding 5k since two negatives equal a positive. While also subtracting the two solutions.
• 2j + 3k = 11              - 2j - 5k = 3         8k = 8
• Now we have to get the variable alone. Divide the coefficient by itself and the solution.
• 2j + 3k = 11              - 2j - 5k = 3         8/8k = 8/8
• After dividing you will find that "k" equals one.
• 2j + 3k = 11              - 2j - 5k = 3         8/8k = 8/8  k = 1
• Plug in k = 1 to solve for j
• 2j + 3(1) = 11 2j + 3 = 11     - 3   -3 2/2j = 8/2 j = 4
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