Yes. Actually,I wanted to ask how to factor quadratics when a=1
Actually, yes.i wanted to know how to factore quadratics when a=1
Ok. That is simple.
Lets take this example. x^2+5x+6. we have to figure out the same two numbers that can give us 5 when added together and 6 when multiplied. the two numbers that come to mind to me are 3 and 2. so we know the factored form is (x+2)(x+3). Do you understand?
Then we look at the original equation and think of two numbers that if we add them it will give us the corresponding b and if we multiply them it was give us the corresponding c. Then we distribute them one at a time and then get the factored form.
Ok. Can I try an example?
So to do this. we know the quadratic form is ax^2+bx+c. To factor,we write it in the form of (x+ )(x+). since quadratics are always at the power of 2. we put an x in each bracket.
Ok i think I understand. can you give me an example to try on my own?
Sure. Let's do this one:x^2+13x+40
Now, the two numbers that come to mind are 8 and 5 since 8x5=40 and 8+5=13. so the factored form is (x+8)(x+5). Is this correct?
Just like you said since we have a quadratic. it is to the power of 2. Thus we write it in the form of (x+ )(x+ ). Next, we have to find two two numbers that will give me 13 and 40 when added and multiplied respectively.
So far, so good.
Yes and it's all because of your wonderful explanation. Thank you very much.
Good job . Seems like you understand completely.
alright so first i'll write the form (x+ )(x+ ) since it is to the power of 2 we have two x's. Then i think of two numbers in which the adding them gives me 8 and multiplying them gives me 40.