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Yea here's a problem. A farm has 50 animals. The animals are chickens and horses. There are 100 legs in total. How many chicken and horse legs are there?
First, you have to figure out your x and y, in this case the x is horses and the y is chickens.
Do you know how to solve a system of equations using substitution?
Then, you have to find the value of y in the equation 4x+2y=100. The value of y is 50.
Then, you're gonna plug the y into 4x+2y=100, and you'll get x=0.
Lastly you just wanna put the x and the y together and you get (0,50)
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