Ok, sure. um... I'm confused about the first question, how do you do it?
The question is 2N3 + C2 -> 2C + 3N2. To do this, you would have to multiply the coefficient with the subscript and since the answer is 6, then that means there are 6 nitrogen, and there should be 6 nitrogen on the product side.
Let's start off by finishing exercise 1, and since we don't have enough time, you should know how to do exercise 2.
You would have to also multiply for carbon, so since there is no coefficient on the reactants side, but there is a subscript, then that means that there is just 2 carbon, same thing for the product side, so there is a coefficient, but no subscript, but since the coefficient is 2, then that means that there are 2 carbon.
Ohhh, ok, I get it now.
Oh, looks like to tutor session just ended, I should get going. But I hope you know how to calculate these problems. Good luck!
