Grouping

Grouping
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  •  You will now factor a grouping problem: x3-5x2+3x-15
  • We should split this problem into two groups
  •  Let's separate x3-5x2 and 3x-15.
  • Now we find the GCF of each individual group
  • The GCF of 3x-15 is 3
  • The GCF of x3-5x2 is x2
  • This leaves us with x2(x-5)+3(x-5)
  • We still aren't done yet. Because what is inside the parenthesis is a perfect match, we can simplify this even further
  • Time for a two for one special. Take that ghost!
  • The answer is (x2+3)(x-5) 
  • How about you do the same type of problem again, but with a little trick...!
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