Today we are gonna learn how to solve this problem on the board . Anyone wanna give it a shot on what to do first .
I'd like to give it a try.
This looks really hard.
I think I know but I'm not gonna try.
First you pick one equation to do, so if we were doing the problem on the left first you would need to subtract 15 with it's self and then with 24 and the left over equation is 9x<9 . Then the last thing you do is divide 9 with it's self, and your finally answer is x<1.
9x+15<24 -15 -15 9x<9 x<1
Good job now who would like to do the second problem.
Well first I think you subtract 1 with it's self and then subtract 1 with 16. Then you get 5x>15 and divide it with 5. Last your finally answer you get is x >3