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  •  Three of the vertices of a parallelogram ABCD are A(-3,1 ),B(4,9) & C(11,-3). Find i) the midpoint of the diagonal AC ii) the fourth vertex D
  • this is the 2nd qns
  • 1)  draw the diagram out
  • A
  • -3
  • 1
  • B
  • -3
  • 9
  • 4
  • C
  • 11
  • A(-3,1)      C(11,-3)
  • x coordinate : 
  • y coordinate :   
  • 2)  find coordinates of midpoint of A & C
  • -3 + 11 2
  • 1 + (-3) 2
  • (4,  -1 )
  • TO SUMMARIZE : midpoint = (x of A - x of B / 2  ,  y of A - y of B / 2 )
  • Let coordinates of  D = (e , f ) midpoint of AC = midpoint of DB ( 4,-1 ) = ( 4+e/2 , 9+f/2 ) 4=            ,  -1 = 
  • D (  8 = 4+e , -2 = 9 + f )  ( e = 4, f = 11 ) (4, 11)
  • 4 + e 2
  • 9 + f 2
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