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Math StoryBoard

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  • Algebra StoryBoard By Drew Newlin
  • Next, I must cancel out a variable. I will use equations 2 and 3.
  • The sum of three numbers is 14. The largest is 4 times the smallest. The sum of the smallest and twice the largest is 18. Find the three numbers.
  • x=lowest number y=middle number z=highest number
  • We will use elimination to solve this problem
  • So first I need to figure out my variables and my equations.
  • 1. x+y+z=14 2. 4x=z 3. x+2z=18
  • You have to multiply eq. 3 by 4 so we can cancel out the x variable.
  • 2. -4x+z=0           z=8          3. 4x+8z=72 9z=72
  • 3. x+16=18       -16  -16 x=2
  • Now I must plug z into equation 2 or 3. I will use 3.
  • 1. 2+y+8=14 y+10=14 y=4
  • I start with eq. 1 which was x+y+z=14. Then plug in 8 for z and 2 for x.
  • Finally I must plug x and z into one of the first three equations. I will use 1.
  • Final Answer: X=2 y=4 z=8
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