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The Puppy Rescue Problemby Jordan Littlepage
OH NO MY PUPPY!!
I WILL LOCK THEM IN A OLD CASTLE
HA HA HA
I need to save my puppy! The old castle is on the other side of the Dark forest, Maybe I can use these unicorns to get there faster
I can use law of cosines to see how far I need to go.
from an overhead map of the land o just so happen to have at this very moment, this is the distance from all of the sides except for the mountain, each line represents the distance between each area
The Dark Forest is 16.4 miles away!! and the unicorn can trot at least 8 miles per hour ill be there in no time .
By using the law of cosines i plug in the numbers from both side a and side cb^2=*^2+14^2-2(8)(14) cos 94which translates to =64 +196-110(-0.07)which would solve to = 16.4=b
I could use the trig functions or soh -cah-toa see the angle and overall size of the of this bridge gap to see if it is safe enough
I made it to the dark forest, but this bridge does not seem safe, we may need a rope just to be safe
In this Situation I only need the hypothenuse for this problem so i would use the formula a^2+b^2 =c^2which would give me the answer 50
sin=48/50 cos=14/50 tan=48/14(simplified) csc=25/24 sec=25/7 cot=7/24
to further show how large the gfap is ai would need to find the sine cos and tangent. the csc, sec, and cot are just the same function but flipped