Trig Project

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• A QB and his Receivers
• A quarterback and receiver are playing catch. While the quarterback is 9 feet away from the receiver, the receiver is sitting on top of a ladder 5 feet up. In order for the quarterback to throw the ball perfectly at the receiver, he uses the trig function tan^-1 (5/9) in order to find the angle of elevation of 29.1° to perfect his throw.
• 9 Feet
• 5 Feet
• Another receiver steps up and this time he is sitting 7 feet up on top of a ladder. The quarterback's angle to the receiver is 33°. In order to figure how far the quarterback is from the receiver, the quarterback uses the trig function 7/tan(33). He then figures out that he is about 10.8 yards away from the receiver.
• 33°
• x Feet
• 7 Feet
• Next in line is another receiver. He sets up another ladder and is sitting 13 feet from the quarterback. The quarterback's angle of elevation is 35°. He wonders how high the receiver is sitting, so he uses the trig function 13/cos(35). He then comes to the conclusion that the receiver is sitting 15.9 feet high.
• 35°
• 13 Feet
• x Feet
• Now that the last receiver is up to catch, the quarterback wants to know how far he should throw the ball. The receiver is 6 feet high and the quarterback wants to throw at an angle of 28°. In order to find the distance, the quarterback uses the trig function of 6/sin(28). He concludes that he should throw to a distance of about 12.8 feet.
• x Feet
• 28°
• 6 Feet
• Since the quarterback and all of the receivers put in work, they can happily go home and rest for the night.
• The End!
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