A baseball accelerates from rest with a constant acceleration of
How fast will it be traveling after it goes 25m ?
If we use the equation Vf²=Vi²+2a(Δx) we can find out how fast it would be going at 25m. Vf is the final velocity, Vi is the initial velocity which is 0 in this case, the A is the acceleration and in this case it would be 8.6, and our Δx is our displacement which in this case is 25m.
Substitute the the variables and the equation should be Vf²=0²+2(8.6m/s²)(25m).After solving the equation we find out that the baseball is traveling at 20.74 m/s.