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  • Ugh. I don't get it, all these terms and equations are merging together. 
  • Okay, let's break it up into sections so it will be easier to understand
  • So, on a rollercoaster centripetal force would be responsible for keeping the coasters moving in a circle?
  • Yes! Good job! 
  • Centripetal Force is present in all objects that move in a circular motion.  So an object moving at a constant speed around a circle requires centripetal force to change its direction.
  • Okay, so if an athlete were to swing a hammer in a circle, they'd be performing Uniform Circular motion? 
  • Now, when discussing centripetal force, the term "Uniform Circular Motion" is introduced. This term basically describes an object that moves in a circle with a constant or uniform speed.
  • Yes, assuming tension is kept on the rope. See it's not that hard. 
  • Okay, in this problem they give us the radius (10.0 m) and period (35.0 sec). So when plugged in v= 2(pi)(10.0m)/35.0 sec, which equals... 1.79 m/s.  
  • We can actually calculate the speed of an object in Uniform Circular Motion. A simple speed calculation would just be v=d/t where d equals distance and t equals time, but to calculate the speed of an object in UCM, d represents the circumference ((2)(pi)(R)) and t represents the period (T). So when everything is plugged in, v= [2(pi)(r)]/T
  • Correct!
  • In number seven, the radius is 45.0 m and the speed stated is 25 m/s. So ac would equal (25)2 /45 which can be simplified to 13.9 m/s2 toward the center of the center.  Wow, i actually get it! 
  • There is also a term called Centripetal Acceleration, this represents the acceleration experienced by an object during Uniform Circular motion.  This also has an equation,  ac  = v2/r,  where ac  represents centripetal acceleration, v equals linear speed, and r represents the radius of the circular path.  Take a look at number seven. 
  • Yup, breaking up the material makes it a lot easier to understand. 
  •  Thank you so much I appreciate it. See you next week!
  • Well, that's all for today, I will see you next week! Make sure to practice some extra problems on page ten. 
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