Ugh. I don't get it, all these terms and equations are merging together.
Okay, let's break it up into sections so it will be easier to understand
So, on a rollercoaster centripetal force would be responsible for keeping the coasters moving in a circle?
Yes! Good job!
Centripetal Force is present in all objects that move in a circular motion. So an object moving at a constant speed around a circle requires centripetal force to change its direction.
Okay, so if an athlete were to swing a hammer in a circle, they'd be performing Uniform Circular motion?
Now, when discussing centripetal force, the term "Uniform Circular Motion" is introduced. This term basically describes an object that moves in a circle with a constant or uniform speed.
Yes, assuming tension is kept on the rope. See it's not that hard.
Okay, in this problem they give us the radius (10.0 m) and period (35.0 sec). So when plugged in v= 2(pi)(10.0m)/35.0 sec, which equals... 1.79 m/s.
We can actually calculate the speed of an object in Uniform Circular Motion. A simple speed calculation would just be v=d/t where d equals distance and t equals time, but to calculate the speed of an object in UCM, d represents the circumference ((2)(pi)(R)) and t represents the period (T). So when everything is plugged in, v= [2(pi)(r)]/T
In number seven, the radius is 45.0 m and the speed stated is 25 m/s. So ac would equal (25)2 /45 which can be simplified to 13.9 m/s2 toward the center of the center. Wow, i actually get it!
There is also a term called Centripetal Acceleration, this represents the acceleration experienced by an object during Uniform Circular motion. This also has an equation, ac = v2/r, where ac represents centripetal acceleration, v equals linear speed, and r represents the radius of the circular path. Take a look at number seven.
Yup, breaking up the material makes it a lot easier to understand.
Thank you so much I appreciate it. See you next week!
Well, that's all for today, I will see you next week! Make sure to practice some extra problems on page ten.