Algebra 2 project

Algebra 2 project
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  • Hey Ryan I need 80% acid solution for a chemistry experiment.
  • But Cove I only have pure acid and I have to use the 3 gallons of 50% acid we have.
  • So how much pure acid should be mixed with 3 gallons of 50% in order to get 80% solution
  • LETS SEE!
  • so the amount of gallons of pure acid is going to be the X
  • Yes!
  • So x+3 = the total number of gallons of acid. Right?
  • So if you multiply 3 by 50% you get the amount of pure acid in the 50% solution
  • Exactly
  • So x+3 multiplied by 80% is going to equal the amount of pure acid in the mix?
  • Okay I understand then 1.5+x=.8(x+3)
  • So get X by its self then divide by what X is multiplied by and you should have your answer.
  • Yes, that's the equation you use to solve.
  • 4.5 GALLONS!!!
  • Thank you Ryan.
  • It’s actually quite simple.
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