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ARGGHHH!! if only I can put the ticket into both boxes, it will raise my chances of winning the lucky draw
Event A = Placing ticket in Box 1 Event B = Placing ticket in Box 2 Event A ∩ B = Aunty Cindy trying to put her ticket in both boxes.
P(A∩B) = Chances of Aunty Cindy placing the ticket in Box 1 and Aunty Cindy placing the ticket in Box 2 at the same time Since Aunty Cindy is unable to place her ticket in both boxes at the same time...… P(A∩B) = 0 Therefore, It is mutually exclusive
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