Wilson's Adventure Around the NeighborhoodBy: Madelyn Musgrove
Wilson loves to spend time outside. He especially loves to watch all the animals outside while he takes walks around the block. Wilson loves math and uses trigonometry to figure out how far his furry friends are from where he is. Watch as he uses sine, cosine, and tangent to figure out angles and measurements.
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Wilson took a walk to his backyard and saw a bunny. He wonders how far up the path it is from him. He knows that the angle of inclination from the bunny to him is 32 degrees, and the inclined length from him and the bunny is 3 ft. He uses sine to calculate how far up the bunny is. He calculates Sin(32) = x/3, which ends up being Sin(32) x3 = length. The length from Wilson to the bunny is 1.6 ft.
3 ft
32 degrees
Next, Wilson spots a baby duck in the pond. He knows that the angle of inclination from the rocks to the duck is 54 degrees, and he is 17 ft away from the rocks. To calculate how far the duck is from the rocks, Wilson uses cosine. He does Cos(54) = x/17, which calculates to Cos(54) x17 = length. The duck is 10 ft away from the rocks.
17 ft
54 degrees
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For Wilson's third trip, he trolled down to the beach. He saw a monkey in a palm tree and wondered how high up it was. The angle of inclination is 73 degrees from Wilson and the monkey, and Wilson is 9 ft away from the palm tree. To calculate how high up the monkey is from the ground, he uses tangent. This gets his to Tan(73) = x/9, which then gives him Tan(73) x/9 = height. The monkey is 29 ft up from the ground
73 degrees
9
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Wilson's last stop is to the rocks, where he sees the sight of a bald eagle. The eagle is 66 ft high, and Wilson is 49 ft away from it. To calculate the angle of inclination, he uses inverse sine. He does Tan-1(66/49). This gave him about 53 ft. The angle of inclination is 53 ft.
66 ft
???
49 ft
He headed back home and thanked trigonometry for helping him fulfill his favorite hobby!
THE END
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