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PATTO THE GATTO TRIG PROJECT

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PATTO THE GATTO TRIG PROJECT
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  • Of course Patto! lets first find angle y, the angle on the edge of the overhang closest to the door! Let's use the inverse cosine!cos-1 x = 14/20x= 45.57°
  • Hi! I am Patto the Gato and got stuck up here! Can you help me get down?
  • 20 ft
  • 14 ft
  • Next Patto, we need to find the height you have to jump at. Let's use tangent to do this!sin 45.57= opp/2014.28=opp
  • 14.28ft
  • x
  • 45.57°
  • 20 ft
  • 14 ft
  • NO PATTO ! YOU FORGOT YOUR FOOD!
  • I can make that! Here I go!
  • 14.28 ft
  • x
  • 14 ft
  • 45.57°
  • 20 ft
  • That's alright! We will just get a latter to put against the building so you can get back up. No big deal! Let's find the angle the ladder will be on the ground.
  • 14.28 ft
  • OH NO! WHAT WILL I EVER DO TO GET MY FOOD??
  • x
  • 14 ft
  • 20 ft
  • 45.57°
  • lets use the inverse of sin to find what angle we should put the ladder at. sin^-1x=14/20x=44.43°Now go get your food!
  • 14.28 ft
  • THANK YOU!
  • 45.57°
  • 14 ft
  • 20 ft
  • THANK YOU!!!
  • No problem Patto enjoy the food!
  • 14.28 ft
  • 44.43°
  • 45.57°
  • 14 ft
  • 20 ft
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