PATTO THE GATTO TRIG PROJECT
Snemalna Knjiga Besedilo
- Of course Patto! lets first find angle y, the angle on the edge of the overhang closest to the door! Let's use the inverse cosine!cos-1 x = 14/20x= 45.57°
- Hi! I am Patto the Gato and got stuck up here! Can you help me get down?
- 20 ft
- 14 ft
- Next Patto, we need to find the height you have to jump at. Let's use tangent to do this!sin 45.57= opp/2014.28=opp
- 14.28ft
- x
- 45.57°
- 20 ft
- 14 ft
- NO PATTO ! YOU FORGOT YOUR FOOD!
- I can make that! Here I go!
- 14.28 ft
- x
- 14 ft
- 45.57°
- 20 ft
- That's alright! We will just get a latter to put against the building so you can get back up. No big deal! Let's find the angle the ladder will be on the ground.
- 14.28 ft
- OH NO! WHAT WILL I EVER DO TO GET MY FOOD??
- x
- 14 ft
- 20 ft
- 45.57°
- lets use the inverse of sin to find what angle we should put the ladder at. sin^-1x=14/20x=44.43°Now go get your food!
- 14.28 ft
- THANK YOU!
- 45.57°
- 14 ft
- 20 ft
- THANK YOU!!!
- No problem Patto enjoy the food!
- 14.28 ft
- 44.43°
- 45.57°
- 14 ft
- 20 ft
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