- See, our problems weren't that hard.
- Yea, it only took us 150 days to do them....
- We're all done and now the flood is gone! Finally!
- Ham and Japeth won’t help me with my trig problem!
- What are you guys in here getting loud about!?
- Because my problem is harder than yours and Japeth’s.
- No way!! You couldn’t even begin to solve my problem! It doesn’t even have numbers in it.
- Alright, alright boys. Shem, we will start with you. What does your problem say?
- My problem says: sinθ, given that cscθ = -5/9 … What does that even mean?
- It’s simple! First, notice that sine (sin) and cosecant (csc) are reciprocals of each other. This means they're inverses of each other and their product is equal to 1. So, substitute -5/9 into the cscθ of the equation sinθ= 1/cscθ. Your equation will look like sinθ= 1/ (-5/9) and you'll solve this by using Keep Change Flip, where you keep the 1, change the division to multiplication, and flip your faction. Therefore cscθ = -5/9, then sinθ =-9/5. Simple as that! Your turn, Ham!
- My problem says: Determine the sign of the trigonometric functions of an angle in standard position with the given measure 283°.
- Alright, so according to All Students Take Calculus, since angle 283° is in quadrant IV, it falls under “Calculus,” or cosine and its reverse, secant. This means that 283° is positive in the quadrant I (All), cosine and secant and is negative in sine, cosecant, tangent, and cotangent. That’s it! Japeth, it’s your turn now.
- Actually, mine is kind of similar to Ham’s. My problem is: tanθ > 0, cosθ < 0 .
- To solve this problem, it is quite like Ham’s problem. tanθ > 0, cosθ < 0 reads as “tangent of theta is greater than 0 and cosine of theta is less than 0.” Greater than 0 means positive and less than 0 means negative. So with this information, find the quadrant that tangent can be positive and cosine can be negative at the same time. This will be quadrant III
- Thanks dad!!!, Look, a dove!