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A Mysterious Wolf with the lost princess
Layla is a girl who lives in a castle. One day, Layla decided to take a walk and gets lost in a forest. Layla is standing 16 feet away from a wolf she sees at 45 degrees. She wonders how far the wolf is. So she uses trig. After she makes the calculations, she sets it up like tan(45) * 16= 16. She soon realizes the wolf is 16 feet away from her.
45 degrees
16 ft
x ft
Since the wolf was an Arctic wolf, she wanted to take it home. Layla decided to get closer, but the Arctic wolf stayed in the same spot. Layla moves 10 ft closer and sees the Arctic wolf at 30 degrees now. She decided to now use sin. She uses x=10/sin (30)= 20 feet. She realizes that she is 20 feet closer to the Arctic wolf.
x
30 degrees
10 feet
The Arctic Wolf then decides to move away 11 feet away . The Lost Princess yelled at him in a 33 degree angle, but he wouldn't listen. She then decides to use trig.to figure out how far he was. She finds out that 11/ tan (33)= 16.9. She figures out he is 16.9 feet away.
wait come back
33 degrees
X
11 Ft
She then starts to look for him.
When she finally found him, she saw his wife and child. She helped them out and feed them everyday. They lived happily ever after, The End!

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