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- Throughout quantities in chemical reactions, we have learned a variety of topics. Some of which include the following:
- mole calculations, conversions, percent calculations, empirical molecular formulas, chemical reactions and ratios.
- If 25g of NaOH reacts with 150g of CuSO4, what is the limiting reactant and how much Na2SO4 will be made?NaOH + CuSO4 - Na2SO4 + Cu(OH)2
- Today we will review questions in this unit! Can anyone solve the question written on the board?
- 2NaOH + CuSO4 - Na2SO4 + Cu(OH)2m(NaOH)=25g | m(CuSO4)=150gnn(NaOH)=m/M | n(CuSO4)=m/M =25g/40g/mol | =150g/159.62g/mol =0.625mol | = 0.9397319mol----------------------------------------2NaOH 0.625 x=0.3125 mols------- = ------- of CuSO4 needed1CuSO4 x NaOH is the limiting reactant
- 2NaOH + CuSO4 - Na2SO4 + Cu(OH)2 2NaOH 0.625 y=0.3125 mol of ------- = ------- Na2SO4 produced1Na2SO4 y When using all the NaOHm=nM M(Na2SO4)=142.05 =(0.3125mol)(142.05g/mol) =44.39g - =44.4gTherefore, 44.4g of NaSO4 will be made.
- Here's a simpler chemistry questions to wrap up this class.What should you do if no one laughs at your chemistry jokes?
- Keep telling them until you get a reaction!
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