LOL! I'll do the job, but you gonna have to buy the fence first. I would suggest rounding to the nearest tenth and then finding how much fencing you need to buy in total feet to fence in the perimeter
Do math you silly willy! Show a full algebraic solution!
DANG! GEE WHIZ! Now how am I supposed to do that!
Guess I gotta do some math Equation Elf, my good friend.. Since I know that my length has to be four feet more than half my width, I could set up the equation l=1/2w+4 for my length. Then, since length times width equals total area, I could set up a final equation of 1/2w+4(w)=180, 180 being my area and w being the unknown width I need to solve for.
SO COOL MRS. TARQUISHA JACQUES!
Ok, Equation Elf, now we solve! We come up with a quadratic equation after subtracting 180 from both sides, and multiplying 1/2w+4 by w. The equation is 1/2w^2+4w-180. Solving, we get the answer 4 plus or minus the square root of 376, and since a width can't be negative, we use a positive answer to get the width of 15.4 feet. We plug this answer into our length equation then, and get an answer of 11.7. Adding the two lengths and widths to get the perimeter, I realize I need 54.2 feet of or 55 feet because I can't buy a decimal amount.