Do you know what a quadratic formula is?
x=
−b±√b2−4ac |
2a |
That looks hard.
It's not o hard. Let's try a problem. We will start with the following: First we want to write the equation in standard form and identify a, b, c
0=x^2+4x+1
This is in standard form.
a=1,b=4,c=1
x=
−b±√b2−4ac |
2a |
a = 1, b = 4, c = 1
x=
−(4)±√42−4(1)(1) |
2(1) |
Substitute the values for a,b,c into the quadratic formula
Simplify using the order of operations
x=
−4+√12 |
2 |
x=
−4−√12 |
2 |
Separate the equation into 2 equations
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
|
Use your calculator to approximate the square root of 12
x≈
−4+3.46 |
2 |
x≈
−4−3.46 |
2 |
Simplify each equation
x | ≈ |
| ||
≈ |
| |||
≈ | −0.27 |
|
Compare the approximate solutions to the graph
The two approximate solutions are x = −0.27 and x = −3.73.
The x-intercepts are right where you expected them to be!
That's all there is to it. Was it as hard as you thought?
Not as hard as I thought but it is a lot of work with a lot of steps
I think you did just great and I am sure you are ready for the test.
Thanks. I think so too.
The End!
Do you know what a quadratic formula is?
x=
−b±√b2−4ac |
2a |
That looks hard.
It's not o hard. Let's try a problem. We will start with the following: First we want to write the equation in standard form and identify a, b, c
0=x^2+4x+1
This is in standard form.
a=1,b=4,c=1
x=
−b±√b2−4ac |
2a |
a = 1, b = 4, c = 1
x=
−(4)±√42−4(1)(1) |
2(1) |
Substitute the values for a,b,c into the quadratic formula
Simplify using the order of operations
x=
−4+√12 |
2 |
x=
−4−√12 |
2 |
Separate the equation into 2 equations
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
|
Use your calculator to approximate the square root of 12
x≈
−4+3.46 |
2 |
x≈
−4−3.46 |
2 |
Simplify each equation
x | ≈ |
| ||
≈ |
| |||
≈ | −0.27 |
|
Compare the approximate solutions to the graph
The two approximate solutions are x = −0.27 and x = −3.73.
The x-intercepts are right where you expected them to be!
That's all there is to it. Was it as hard as you thought?
Not as hard as I thought but it is a lot of work with a lot of steps
I think you did just great and I am sure you are ready for the test.
Thanks. I think so too.
The End!
Do you know what a quadratic formula is?
x=
−b±√b2−4ac |
2a |
That looks hard.
It's not o hard. Let's try a problem. We will start with the following: First we want to write the equation in standard form and identify a, b, c
0=x^2+4x+1
This is in standard form.
a=1,b=4,c=1
x=
−b±√b2−4ac |
2a |
a = 1, b = 4, c = 1
x=
−(4)±√42−4(1)(1) |
2(1) |
Substitute the values for a,b,c into the quadratic formula
Simplify using the order of operations
x=
−4+√12 |
2 |
x=
−4−√12 |
2 |
Separate the equation into 2 equations
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
|
Use your calculator to approximate the square root of 12
x≈
−4+3.46 |
2 |
x≈
−4−3.46 |
2 |
Simplify each equation
x | ≈ |
| ||
≈ |
| |||
≈ | −0.27 |
|
Compare the approximate solutions to the graph
The two approximate solutions are x = −0.27 and x = −3.73.
The x-intercepts are right where you expected them to be!
That's all there is to it. Was it as hard as you thought?
Not as hard as I thought but it is a lot of work with a lot of steps
I think you did just great and I am sure you are ready for the test.
Thanks. I think so too.
The End!
Do you know what a quadratic formula is?
x=
−b±√b2−4ac |
2a |
That looks hard.
It's not o hard. Let's try a problem. We will start with the following: First we want to write the equation in standard form and identify a, b, c
0=x^2+4x+1
This is in standard form.
a=1,b=4,c=1
x=
−b±√b2−4ac |
2a |
a = 1, b = 4, c = 1
x=
−(4)±√42−4(1)(1) |
2(1) |
Substitute the values for a,b,c into the quadratic formula
Simplify using the order of operations
x=
−4+√12 |
2 |
x=
−4−√12 |
2 |
Separate the equation into 2 equations
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
|
Use your calculator to approximate the square root of 12
x≈
−4+3.46 |
2 |
x≈
−4−3.46 |
2 |
Simplify each equation
x | ≈ |
| ||
≈ |
| |||
≈ | −0.27 |
|
Compare the approximate solutions to the graph
The two approximate solutions are x = −0.27 and x = −3.73.
The x-intercepts are right where you expected them to be!
That's all there is to it. Was it as hard as you thought?
Not as hard as I thought but it is a lot of work with a lot of steps
I think you did just great and I am sure you are ready for the test.
Thanks. I think so too.
The End!
Do you know what a quadratic formula is?
x=
−b±√b2−4ac |
2a |
That looks hard.
It's not o hard. Let's try a problem. We will start with the following: First we want to write the equation in standard form and identify a, b, c
0=x^2+4x+1
This is in standard form.
a=1,b=4,c=1
x=
−b±√b2−4ac |
2a |
a = 1, b = 4, c = 1
x=
−(4)±√42−4(1)(1) |
2(1) |
Substitute the values for a,b,c into the quadratic formula
Simplify using the order of operations
x=
−4+√12 |
2 |
x=
−4−√12 |
2 |
Separate the equation into 2 equations
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
|
Use your calculator to approximate the square root of 12
x≈
−4+3.46 |
2 |
x≈
−4−3.46 |
2 |
Simplify each equation
x | ≈ |
| ||
≈ |
| |||
≈ | −0.27 |
|
Compare the approximate solutions to the graph
The two approximate solutions are x = −0.27 and x = −3.73.
The x-intercepts are right where you expected them to be!
That's all there is to it. Was it as hard as you thought?
Not as hard as I thought but it is a lot of work with a lot of steps
I think you did just great and I am sure you are ready for the test.
Thanks. I think so too.
The End!
Do you know what a quadratic formula is?
x=
−b±√b2−4ac |
2a |
That looks hard.
It's not o hard. Let's try a problem. We will start with the following: First we want to write the equation in standard form and identify a, b, c
0=x^2+4x+1
This is in standard form.
a=1,b=4,c=1
x=
−b±√b2−4ac |
2a |
a = 1, b = 4, c = 1
x=
−(4)±√42−4(1)(1) |
2(1) |
Substitute the values for a,b,c into the quadratic formula
Simplify using the order of operations
x=
−4+√12 |
2 |
x=
−4−√12 |
2 |
Separate the equation into 2 equations
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
|
Use your calculator to approximate the square root of 12
x≈
−4+3.46 |
2 |
x≈
−4−3.46 |
2 |
Simplify each equation
x | ≈ |
| ||
≈ |
| |||
≈ | −0.27 |
|
Compare the approximate solutions to the graph
The two approximate solutions are x = −0.27 and x = −3.73.
The x-intercepts are right where you expected them to be!
That's all there is to it. Was it as hard as you thought?
Not as hard as I thought but it is a lot of work with a lot of steps
I think you did just great and I am sure you are ready for the test.
Thanks. I think so too.
The End!
Do you know what a quadratic formula is?
x=
−b±√b2−4ac |
2a |
That looks hard.
It's not o hard. Let's try a problem. We will start with the following: First we want to write the equation in standard form and identify a, b, c
0=x^2+4x+1
This is in standard form.
a=1,b=4,c=1
x=
−b±√b2−4ac |
2a |
a = 1, b = 4, c = 1
x=
−(4)±√42−4(1)(1) |
2(1) |
Substitute the values for a,b,c into the quadratic formula
Simplify using the order of operations
x=
−4+√12 |
2 |
x=
−4−√12 |
2 |
Separate the equation into 2 equations
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
|
Use your calculator to approximate the square root of 12
x≈
−4+3.46 |
2 |
x≈
−4−3.46 |
2 |
Simplify each equation
x | ≈ |
| ||
≈ |
| |||
≈ | −0.27 |
|
Compare the approximate solutions to the graph
The two approximate solutions are x = −0.27 and x = −3.73.
The x-intercepts are right where you expected them to be!
That's all there is to it. Was it as hard as you thought?
Not as hard as I thought but it is a lot of work with a lot of steps
I think you did just great and I am sure you are ready for the test.
Thanks. I think so too.
The End!
Do you know what a quadratic formula is?
x=
−b±√b2−4ac |
2a |
That looks hard.
It's not o hard. Let's try a problem. We will start with the following: First we want to write the equation in standard form and identify a, b, c
0=x^2+4x+1
This is in standard form.
a=1,b=4,c=1
x=
−b±√b2−4ac |
2a |
a = 1, b = 4, c = 1
x=
−(4)±√42−4(1)(1) |
2(1) |
Substitute the values for a,b,c into the quadratic formula
Simplify using the order of operations
x=
−4+√12 |
2 |
x=
−4−√12 |
2 |
Separate the equation into 2 equations
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
|
Use your calculator to approximate the square root of 12
x≈
−4+3.46 |
2 |
x≈
−4−3.46 |
2 |
Simplify each equation
x | ≈ |
| ||
≈ |
| |||
≈ | −0.27 |
|
Compare the approximate solutions to the graph
The two approximate solutions are x = −0.27 and x = −3.73.
The x-intercepts are right where you expected them to be!
That's all there is to it. Was it as hard as you thought?
Not as hard as I thought but it is a lot of work with a lot of steps
I think you did just great and I am sure you are ready for the test.
Thanks. I think so too.
The End!
Do you know what a quadratic formula is?
x=
−b±√b2−4ac |
2a |
That looks hard.
It's not o hard. Let's try a problem. We will start with the following: First we want to write the equation in standard form and identify a, b, c
0=x^2+4x+1
This is in standard form.
a=1,b=4,c=1
x=
−b±√b2−4ac |
2a |
a = 1, b = 4, c = 1
x=
−(4)±√42−4(1)(1) |
2(1) |
Substitute the values for a,b,c into the quadratic formula
Simplify using the order of operations
x=
−4+√12 |
2 |
x=
−4−√12 |
2 |
Separate the equation into 2 equations
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
|
Use your calculator to approximate the square root of 12
x≈
−4+3.46 |
2 |
x≈
−4−3.46 |
2 |
Simplify each equation
x | ≈ |
| ||
≈ |
| |||
≈ | −0.27 |
|
Compare the approximate solutions to the graph
The two approximate solutions are x = −0.27 and x = −3.73.
The x-intercepts are right where you expected them to be!
That's all there is to it. Was it as hard as you thought?
Not as hard as I thought but it is a lot of work with a lot of steps
I think you did just great and I am sure you are ready for the test.
Thanks. I think so too.
The End!
Do you know what a quadratic formula is?
x=
−b±√b2−4ac |
2a |
That looks hard.
It's not o hard. Let's try a problem. We will start with the following: First we want to write the equation in standard form and identify a, b, c
0=x^2+4x+1
This is in standard form.
a=1,b=4,c=1
x=
−b±√b2−4ac |
2a |
a = 1, b = 4, c = 1
x=
−(4)±√42−4(1)(1) |
2(1) |
Substitute the values for a,b,c into the quadratic formula
Simplify using the order of operations
x=
−4+√12 |
2 |
x=
−4−√12 |
2 |
Separate the equation into 2 equations
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
|
Use your calculator to approximate the square root of 12
x≈
−4+3.46 |
2 |
x≈
−4−3.46 |
2 |
Simplify each equation
x | ≈ |
| ||
≈ |
| |||
≈ | −0.27 |
|
Compare the approximate solutions to the graph
The two approximate solutions are x = −0.27 and x = −3.73.
The x-intercepts are right where you expected them to be!
That's all there is to it. Was it as hard as you thought?
Not as hard as I thought but it is a lot of work with a lot of steps
I think you did just great and I am sure you are ready for the test.
Thanks. I think so too.
The End!
Do you know what a quadratic formula is?
x=
−b±√b2−4ac |
2a |
That looks hard.
It's not o hard. Let's try a problem. We will start with the following: First we want to write the equation in standard form and identify a, b, c
0=x^2+4x+1
This is in standard form.
a=1,b=4,c=1
x=
−b±√b2−4ac |
2a |
a = 1, b = 4, c = 1
x=
−(4)±√42−4(1)(1) |
2(1) |
Substitute the values for a,b,c into the quadratic formula
Simplify using the order of operations
x=
−4+√12 |
2 |
x=
−4−√12 |
2 |
Separate the equation into 2 equations
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
|
Use your calculator to approximate the square root of 12
x≈
−4+3.46 |
2 |
x≈
−4−3.46 |
2 |
Simplify each equation
x | ≈ |
| ||
≈ |
| |||
≈ | −0.27 |
|
Compare the approximate solutions to the graph
The two approximate solutions are x = −0.27 and x = −3.73.
The x-intercepts are right where you expected them to be!
That's all there is to it. Was it as hard as you thought?
Not as hard as I thought but it is a lot of work with a lot of steps
I think you did just great and I am sure you are ready for the test.
Thanks. I think so too.
The End!
Do you know what a quadratic formula is?
x=
−b±√b2−4ac |
2a |
That looks hard.
It's not o hard. Let's try a problem. We will start with the following: First we want to write the equation in standard form and identify a, b, c
0=x^2+4x+1
This is in standard form.
a=1,b=4,c=1
x=
−b±√b2−4ac |
2a |
a = 1, b = 4, c = 1
x=
−(4)±√42−4(1)(1) |
2(1) |
Substitute the values for a,b,c into the quadratic formula
Simplify using the order of operations
x=
−4+√12 |
2 |
x=
−4−√12 |
2 |
Separate the equation into 2 equations
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
|
Use your calculator to approximate the square root of 12
x≈
−4+3.46 |
2 |
x≈
−4−3.46 |
2 |
Simplify each equation
x | ≈ |
| ||
≈ |
| |||
≈ | −0.27 |
|
Compare the approximate solutions to the graph
The two approximate solutions are x = −0.27 and x = −3.73.
The x-intercepts are right where you expected them to be!
That's all there is to it. Was it as hard as you thought?
Not as hard as I thought but it is a lot of work with a lot of steps
I think you did just great and I am sure you are ready for the test.
Thanks. I think so too.
The End!
Do you know what a quadratic formula is?
x=
−b±√b2−4ac |
2a |
That looks hard.
It's not o hard. Let's try a problem. We will start with the following: First we want to write the equation in standard form and identify a, b, c
0=x^2+4x+1
This is in standard form.
a=1,b=4,c=1
x=
−b±√b2−4ac |
2a |
a = 1, b = 4, c = 1
x=
−(4)±√42−4(1)(1) |
2(1) |
Substitute the values for a,b,c into the quadratic formula
Simplify using the order of operations
x=
−4+√12 |
2 |
x=
−4−√12 |
2 |
Separate the equation into 2 equations
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
| ||
x=
|
Use your calculator to approximate the square root of 12
x≈
−4+3.46 |
2 |
x≈
−4−3.46 |
2 |
Simplify each equation
x | ≈ |
| ||
≈ |
| |||
≈ | −0.27 |
|
Compare the approximate solutions to the graph
The two approximate solutions are x = −0.27 and x = −3.73.
The x-intercepts are right where you expected them to be!
That's all there is to it. Was it as hard as you thought?
Not as hard as I thought but it is a lot of work with a lot of steps
I think you did just great and I am sure you are ready for the test.
Thanks. I think so too.
The End!