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Let y be the number of deer in the national park t years after the year 2016: y=abt

A national park has a population of 5000 deer in the year 2016. Conservationists are concerned because the deer population is decreasing at the rate of 7% per year. If the population continues to decrease at this rate, how long will it take until the population is only 3000 deer?

r=0.07 b=1+r=1+r(-0.07)=0.93 and the initial population is a=5000

r=0.07 b=1+r=1+r(-0.07)=0.93 and the initial population is a=5000

The exponential decay function is y=5000(0.93)t

3000=5000(0.93)t


To find when the population will be 3000, substitute y = 3000

Next, divide both sides by 5000 to isolate the exponential expression

3000/5000=5000/5000(0.93)20.6=0.93t

Rewrite the equation in logarithmic form; then use the change of base formula to evaluate.

t=log0.93(0.6)
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Let y be the number of deer in the national park t years after the year 2016: y=abt

A national park has a population of 5000 deer in the year 2016. Conservationists are concerned because the deer population is decreasing at the rate of 7% per year. If the population continues to decrease at this rate, how long will it take until the population is only 3000 deer?

r=0.07 b=1+r=1+r(-0.07)=0.93 and the initial population is a=5000

r=0.07 b=1+r=1+r(-0.07)=0.93 and the initial population is a=5000

The exponential decay function is y=5000(0.93)t

3000=5000(0.93)t


To find when the population will be 3000, substitute y = 3000

Next, divide both sides by 5000 to isolate the exponential expression

3000/5000=5000/5000(0.93)20.6=0.93t

Rewrite the equation in logarithmic form; then use the change of base formula to evaluate.

t=log0.93(0.6)
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Let y be the number of deer in the national park t years after the year 2016: y=abt

A national park has a population of 5000 deer in the year 2016. Conservationists are concerned because the deer population is decreasing at the rate of 7% per year. If the population continues to decrease at this rate, how long will it take until the population is only 3000 deer?

r=0.07 b=1+r=1+r(-0.07)=0.93 and the initial population is a=5000

r=0.07 b=1+r=1+r(-0.07)=0.93 and the initial population is a=5000

The exponential decay function is y=5000(0.93)t

3000=5000(0.93)t


To find when the population will be 3000, substitute y = 3000

Next, divide both sides by 5000 to isolate the exponential expression

3000/5000=5000/5000(0.93)20.6=0.93t

Rewrite the equation in logarithmic form; then use the change of base formula to evaluate.

t=log0.93(0.6)
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Let y be the number of deer in the national park t years after the year 2016: y=abt

A national park has a population of 5000 deer in the year 2016. Conservationists are concerned because the deer population is decreasing at the rate of 7% per year. If the population continues to decrease at this rate, how long will it take until the population is only 3000 deer?

r=0.07 b=1+r=1+r(-0.07)=0.93 and the initial population is a=5000

r=0.07 b=1+r=1+r(-0.07)=0.93 and the initial population is a=5000

The exponential decay function is y=5000(0.93)t

3000=5000(0.93)t


To find when the population will be 3000, substitute y = 3000

Next, divide both sides by 5000 to isolate the exponential expression

3000/5000=5000/5000(0.93)20.6=0.93t

Rewrite the equation in logarithmic form; then use the change of base formula to evaluate.

t=log0.93(0.6)
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Let y be the number of deer in the national park t years after the year 2016: y=abt

A national park has a population of 5000 deer in the year 2016. Conservationists are concerned because the deer population is decreasing at the rate of 7% per year. If the population continues to decrease at this rate, how long will it take until the population is only 3000 deer?

r=0.07 b=1+r=1+r(-0.07)=0.93 and the initial population is a=5000

r=0.07 b=1+r=1+r(-0.07)=0.93 and the initial population is a=5000

The exponential decay function is y=5000(0.93)t

3000=5000(0.93)t


To find when the population will be 3000, substitute y = 3000

Next, divide both sides by 5000 to isolate the exponential expression

3000/5000=5000/5000(0.93)20.6=0.93t

Rewrite the equation in logarithmic form; then use the change of base formula to evaluate.

t=log0.93(0.6)
Create your own at Storyboard That









Let y be the number of deer in the national park t years after the year 2016: y=abt

A national park has a population of 5000 deer in the year 2016. Conservationists are concerned because the deer population is decreasing at the rate of 7% per year. If the population continues to decrease at this rate, how long will it take until the population is only 3000 deer?

r=0.07 b=1+r=1+r(-0.07)=0.93 and the initial population is a=5000

r=0.07 b=1+r=1+r(-0.07)=0.93 and the initial population is a=5000

The exponential decay function is y=5000(0.93)t

3000=5000(0.93)t


To find when the population will be 3000, substitute y = 3000

Next, divide both sides by 5000 to isolate the exponential expression

3000/5000=5000/5000(0.93)20.6=0.93t

Rewrite the equation in logarithmic form; then use the change of base formula to evaluate.

t=log0.93(0.6)
Create your own at Storyboard That









Let y be the number of deer in the national park t years after the year 2016: y=abt

A national park has a population of 5000 deer in the year 2016. Conservationists are concerned because the deer population is decreasing at the rate of 7% per year. If the population continues to decrease at this rate, how long will it take until the population is only 3000 deer?

r=0.07 b=1+r=1+r(-0.07)=0.93 and the initial population is a=5000

r=0.07 b=1+r=1+r(-0.07)=0.93 and the initial population is a=5000

The exponential decay function is y=5000(0.93)t

3000=5000(0.93)t


To find when the population will be 3000, substitute y = 3000

Next, divide both sides by 5000 to isolate the exponential expression

3000/5000=5000/5000(0.93)20.6=0.93t

Rewrite the equation in logarithmic form; then use the change of base formula to evaluate.

t=log0.93(0.6)
Create your own at Storyboard That









Let y be the number of deer in the national park t years after the year 2016: y=abt

A national park has a population of 5000 deer in the year 2016. Conservationists are concerned because the deer population is decreasing at the rate of 7% per year. If the population continues to decrease at this rate, how long will it take until the population is only 3000 deer?

r=0.07 b=1+r=1+r(-0.07)=0.93 and the initial population is a=5000

r=0.07 b=1+r=1+r(-0.07)=0.93 and the initial population is a=5000

The exponential decay function is y=5000(0.93)t

3000=5000(0.93)t


To find when the population will be 3000, substitute y = 3000

Next, divide both sides by 5000 to isolate the exponential expression

3000/5000=5000/5000(0.93)20.6=0.93t

Rewrite the equation in logarithmic form; then use the change of base formula to evaluate.

t=log0.93(0.6)
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  • 
  • A national park has a population of 5000 deer in the year 2016. Conservationists are concerned because the deer population is decreasing at the rate of 7% per year. If the population continues to decrease at this rate, how long will it take until the population is only 3000 deer?
  • Let y be the number of deer in the national park t years after the year 2016: y=abt
  • r=0.07 & b=1+r=1+r(-0.07)=0.93 and the initial population is a=5000
  • 
  • r=0.07 & b=1+r=1+r(-0.07)=0.93 and the initial population is a=5000
  • The exponential decay function is y=5000(0.93)t
  • 3000=5000(0.93)t
  • To find when the population will be 3000, substitute y = 3000
  • 3000/5000=5000/5000(0.93)20.6=0.93t
  • Next, divide both sides by 5000 to isolate the exponential expression
  • Rewrite the equation in logarithmic form; then use the change of base formula to evaluate.
  • t=log0.93(0.6)
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